謝謝鋼琴老師的詳解 !!
點出了我思考這題的不足之處 !!
感謝您 !! 感謝 !! ^^
105 台南二中
版主: thepiano
Re: 105 台南二中
填充第 4 題
這題有個比較簡單的做法
b_1 = 1/4
b_2 = 5/4^2 - 1/4 = 1/4^2
b_3 = 5/4^3 - 1/4^2 = 1/4^3
:
:
b_n = 1/4^n
S_n = {(1/4) * [1 - (1/4)^n]} / (1 - 1/4) = (1/3)[1 - (1/4)^n]
|S_n - 1/3| = (1/3)(1/4)^n ≦ 1/3000
(1/4)^n ≦ 1/1000
n 取 5
這題有個比較簡單的做法
b_1 = 1/4
b_2 = 5/4^2 - 1/4 = 1/4^2
b_3 = 5/4^3 - 1/4^2 = 1/4^3
:
:
b_n = 1/4^n
S_n = {(1/4) * [1 - (1/4)^n]} / (1 - 1/4) = (1/3)[1 - (1/4)^n]
|S_n - 1/3| = (1/3)(1/4)^n ≦ 1/3000
(1/4)^n ≦ 1/1000
n 取 5