107 新北市聯招
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Re: 107 新北市聯招
計算第 1 題
答案
(1) b(x - y)(y - z)(z - x)(x + y + z + a)
(2) 參考附件
答案
(1) b(x - y)(y - z)(z - x)(x + y + z + a)
(2) 參考附件
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Re: 107 新北市聯招
填充第 3 題
h(x) = f(x) - g(x) = 2x^3 + ax^2 + bx + c
h(1) = 2，h(2) = 3，h(3) = 4
可求出 h(x) = f(x) - g(x) = 2x^3 - 12x^2 + 23x - 11
3f(1) - 3f(2) + f(3) = 3g(1) - 3g(2) + g(3) + 1 = 5
3g(1) - 3g(2) + g(3) = g(0) = 4
f(0) = -7
h(x) = f(x) - g(x) = 2x^3 + ax^2 + bx + c
h(1) = 2，h(2) = 3，h(3) = 4
可求出 h(x) = f(x) - g(x) = 2x^3 - 12x^2 + 23x - 11
3f(1) - 3f(2) + f(3) = 3g(1) - 3g(2) + g(3) + 1 = 5
3g(1) - 3g(2) + g(3) = g(0) = 4
f(0) = -7